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Master Engineering Disciplines with Structured Notes

Comprehensive academic lecture notes, exam-oriented unit summaries, laboratory manuals, and previous year question papers designed strictly for university students.

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University Syllabi

AKTU & AICTE aligned semester credit guidelines.

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Exam Question Papers

Previous 5 years solved university semester papers.

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Lab Manuals & Viva

Practical codes with outputs and interview questions.

Core Subjects & Units Hub

Click on any specific unit to immediately view its lecture notes below

🎨 Computer Graphics (CG)

Scan Conversion, Bresenham Line & Circle, 2D/3D Transformations, Viewing & Clipping.

Unit 1: Raster Scan, DDA & Bresenham →
Unit 2: 2D & 3D Transformations →
Unit 3: Sutherland-Hodgman & Clipping →
Unit 4: Hidden Surface Elimination →

🧠 Machine Learning (ML / MLT)

Supervised/Unsupervised Learning, Regression, Decision Trees, SVM, Neural Nets & Clustering.

Unit 1: Linear & Logistic Regression →
Unit 2: Decision Trees & Support Vector (SVM) →
Unit 3: K-Means & Dimensionality Reduction →
Unit 4: Neural Networks & Gradient Descent →

🤖 Artificial Intelligence (AI)

Search Algorithms, First Order Logic, Probabilistic Reasoning, Expert Systems & Robotics.

Unit 1: Propositional Logic & Connectives →
Unit 2: Probabilistic Reasoning & Uncertainty →
Unit 3: State Space Search & Heuristics →
Unit 4: First Order Predicate Logic (FOL) →

🗄️ Database Management (DBMS)

ER-Modeling, Relational Algebra, SQL Queries, Normalization (1NF-BCNF) and ACID Transactions.

Unit 1: ER Model, Entities & Attributes →
Unit 2: Functional Dependencies & 1NF to BCNF →
Unit 3: ACID Properties & Concurrency Control →
Unit 4: Relational Algebra & Complex SQL Joins →

🌲 Data Structures & Algorithms

Arrays, Linked Lists, Stacks, Queues, Binary Trees, Graphs, Sorting & Asymptotic Analysis.

Unit 1: Arrays, Matrices & Recursion →
Unit 2: Stacks, Queues & Infix-to-Postfix →
Unit 3: Binary Trees, BST & AVL Rotations →
Unit 4: Graphs (BFS, DFS, Dijkstra, MST) →

⚡ Operating Systems

Process Scheduling, Deadlocks, Synchronization, Virtual Memory, Paging and Disk Management.

Unit 1: Process States, PCB & Multi-Threading →
Unit 2: CPU Scheduling (FCFS, SJF, RR) →
Unit 3: Deadlocks, Semaphores & Banker's Algo →
Unit 4: Virtual Memory, Paging & Disk Scheduling →

🌐 Computer Networks

OSI & TCP/IP Models, Error Detection, IPv4 Subnetting, Routing Protocols and TCP Handshake.

Unit 1: OSI vs TCP/IP Protocol Architectures →
Unit 2: Data Link Layer, Framing & Sliding Window →
Unit 3: IPv4 Addressing, Subnetting & Routing →
Unit 4: Transport Layer (TCP 3-Way Handshake) →

⚙️ Design of Algorithms (DAA)

Asymptotic Notations, Divide & Conquer, Dynamic Programming, Greedy Approach & Backtracking.

Unit 1: Time Complexity, Master's Theorem →
Unit 2: 0/1 Knapsack & Dynamic Programming →
Unit 3: Greedy Methods & Graph Algorithms →
Viewing All Lectures

Regular expression

Regular expression

  • Regular expression is a sequence of pattern that defines a string. It is used to denote regular languages.
  • It is also used to match character combinations in strings. String searching algorithm used this pattern to find the operations on string.
  • In regular expression, x* means zero or more occurrence of x. It can generate {e, x, xx, xxx, xxxx,.....}
  • In regular expression, x+ means one or more occurrence of x. It can generate {x, xx, xxx, xxxx,.....}

Operations on Regular Language

The various operations on regular language are:

Union: If L and M are two regular languages then their union L U M is also a union.

L U M = {s | s is in L or s is in M} 


Intersection: If L and M are two regular languages then their intersection is also an intersection.

L ⋂ M = {st | s is in L and t is in M}  


Kleene closure: If L is a regular language then its kleene closure L1* will also be a regular language.

L* = Zero or more occurrence of language L.


Example

Write the regular expression for the language:

L = {abn w:n ≥ 3, w ∈ (a,b)+}


Solution:

The string of language L starts with "a" followed by atleast three b's. Itcontains atleast one "a" or one "b" that is string are like abbba, abbbbbba, abbbbbbbb, abbbb.....a

So regular expression is:

r= ab3b* (a+b)+

Here + is a positive closure i.e. (a+b)+ = (a+b)* - ∈


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